已知：(aaaaa+aaaab+aaaba)×aaabb-aaaba×aaaba = O

     (aaaab+aaaba+aaabb)×aabaa-aabaa×aabaa = T

     (aaaba+aaabb+aabaa)×aabab-aabba×aabba = W

那么：(aaabb+aabaa+aabab)×aabba-abaaa×abaaa = ？